# What is the smallest number that leaves a remainder of 2 when divided by 3, 4, 5, and 6 ?

What is the smallest number that leaves a remainder of 2 when divided by 3, 4, 5, and 6 ?

A. 56

B. 128

C. 62

D. 32

**Answer : **C. 62

## Explanation:

Take the lcm of 3 , 4 , 5 , 6.

3 = 3×1

4 = 2×2

5 = 5×1

6 = 2×3

LCM = 2 × 2 × 3 × 5 = 60

Therefore 60 is the number that is completely divisible by these numbers. But we have to find the smallest number that leaves remainder 2.

Answer : 60 + 2 = 62