A number is divided by 5, 3, 2 successively in order to get remainders of 0, 2, 1 respectively. What will be the remainder when the same number is divided by 2, 3, 5 respectively ?



A number is divided by 5, 3, 2 successively in order to get remainders of 0, 2, 1 respectively. What will be the remainder when the same number is divided by 2, 3, 5 respectively ?

A. 4, 3, 2

B. 1, 0, 4

C. 2, 1, 3

D. 4, 1, 2

Answer : B. 1, 0, 4...

Explanation:


    Let the number = N.
    Now N = 5K
    K = 3L + 2
    L = 2M + 1
    K = 3 (2M + 1) + 2
        = 6M + 5
    N = 5 (6M + 5)
         = 30 M + 25.

For M = 0 we get the least number as 25. Now when 25 is divided by 2, we get 12 as quotient and 1 as remainder.
When 12 is divided by 3 we get 4 as quotient, and 0 as remainder. When 4 is divided by 5 we get 4 as remainder.


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