A box contains 4 red, 3 white and 2 blue balls. Three balls are drawn at random. Find out the number of ways of selecting the balls of different colours ?

A. 12

B. 24

C. 48

D. 168

Answer : B. 24

Explanation:

1 red ball can be selected in 4C1 ways 1 white ball can be selected in 3C1 ways 1 blue ball can be selected in 2C1 ways
Total number of ways = 4C1 x 3C1 x 2C1 = 4 x 3 x 2 = 24.

 

  • Please note that we have multiplied the combination results, we use to add when their is OR condition, and we use to multiply when there is AND condition.
  • In this question it is AND as 1 red AND 1 White AND 1 Blue, so we multiplied

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