How many 3-digit numbers can be formed from the digits 2, 3, 5, 6, 7 and 9, which are divisible by 5 and none of the digits is repeated ?



How many 3-digit numbers can be formed from the digits 2, 3, 5, 6, 7 and 9, which are divisible by 5 and none of the digits is repeated ?

A. 5

B. 10

C. 15

D. 20

Answer : D. 20


Explanation:

    Since each desired number is divisible by 5, so we must have 5 at the unit place. So, there is 1 way of doing it.
    The tens place can now be filled by any of the remaining 5 digits (2, 3, 6, 7, 9). So, there are 5 ways of filling the tens place.
    The hundreds place can now be filled by any of the remaining 4 digits. So, there are 4 ways of filling it.
    Required number of ways = (1 x 5 x 4) = 20.


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