# In a box, there are 8 red, 7 blue and 6 green balls. One ball is picked up randomly. What is the probability that it is neither red nor green ?

In a box, there are 8 red, 7 blue and 6 green balls. One ball is picked up randomly. What is the probability that it is neither red nor green ?

A. 1/3

B. 3/4

C. 7/19

D. 8/21

E. 9/21

### **Answer : ** A. 1/3

## Explanation:

Total number of balls = (8 + 7 + 6) = 21.

Let E = event that the ball drawn is neither red nor green

= event that the ball drawn is blue.

n(E) = 7

P(E) = n(E)/n(S)

= 7/21

= 1/3 .