In a box, there are 8 red, 7 blue and 6 green balls. One ball is picked up randomly. What is the probability that it is neither red nor green ?



In a box, there are 8 red, 7 blue and 6 green balls. One ball is picked up randomly. What is the probability that it is neither red nor green ?

A. 1/3

B. 3/4

C. 7/19

D. 8/21

E. 9/21

Answer : A. 1/3


Explanation:

    Total number of balls = (8 + 7 + 6) = 21.
    Let E = event that the ball drawn is neither red nor green
               = event that the ball drawn is blue.
    n(E) = 7
    P(E) = n(E)/n(S)
    = 7/21
    = 1/3 .


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