Three unbiased coins are tossed. What is the probability of getting at most two heads ?



Three unbiased coins are tossed. What is the probability of getting at most two heads ?

A. 3/4

B. 1/4

C. 3/8

D. 7/8

Answer : D. 7/8...


Explanation:


    Here, S = {TTT, TTH, THT, HTT, THH, HTH, HHT, HHH}
    Let E = event of getting at most two heads.
    Then E = {TTT, TTH, THT, HTT, THH, HTH, HHT}
    P(E) = n(E)/n(S)
    = 7/8.


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