Tickets numbered 1 to 20 are mixed up and then a ticket is drawn at random. What is the probability that the ticket drawn has a number which is a multiple of 3 or 5 ?



Tickets numbered 1 to 20 are mixed up and then a ticket is drawn at random. What is the probability that the ticket drawn has a number which is a multiple of 3 or 5 ?

A. 1/2

B. 2/5

C. 8/12

D. 9/20

Answer : D. 9/20...


Explanation:


    Here, S = {1, 2, 3, 4, 19, 20}.
    Let E = event of getting a multiple of 3 or 5
    = {3, 6 , 9, 12, 15, 18, 5, 10, 20}.
    P(E) = n(E) / n(S)
    = 9/20


Related Searches to Tickets numbered 1 to 20 are mixed up and then a ticket is drawn at random. What is the probability that the ticket drawn has a number which is a multiple of 3 or 5 ?