# Tickets numbered 1 to 20 are mixed up and then a ticket is drawn at random. What is the probability that the ticket drawn has a number which is a multiple of 3 or 5 ?

Tickets numbered 1 to 20 are mixed up and then a ticket is drawn at random. What is the probability that the ticket drawn has a number which is a multiple of 3 or 5 ?

A. 1/2

B. 2/5

C. 8/12

D. 9/20

**Answer : ** D. 9/20...

## Explanation:

Here, S = {1, 2, 3, 4, 19, 20}.

Let E = event of getting a multiple of 3 or 5

= {3, 6 , 9, 12, 15, 18, 5, 10, 20}.

P(E) = n(E) / n(S)

= 9/20