Assuming the number is x
(42 – 28)% of x = 210
14% of x =210
14/100*x=210
x = 210 * 100/14
x=1500
Therefore the number is 1500

If the price of a commodity increases by R%, then the reduction in consumption so as not to increase the expenditure is [ (R / 100 + R) * 100 ]%
Here R% = 25%
Hence % decrease in the consumption of sugar [ (25 / 100 + 25) * 100 ]%
= [ (25 / 125) * 100 ]%
= [ (1 / 5) * 100 ]%
= 20%

Let the number of men in the village is x.
Number of women in the village is (8000 – x)
If 6% men and 10% women are added population becomes 8600,
x(106 / 100) + (8000 – x) (110 / 100) = 8600
[(110 – 106) / 100] * x = 8800 – 8600
x = 200 * 100 / 4 = 5000
Hence the number of men in the village is 5000.

20% means for every 100 rupees 20 rupees decreases
We have 600 rupees = 6 * 20 = 120
So, 120/5 = 24

Each year decreses by 10% and for continuous 4years
350000 * (90/100) * (90/100) * (90/100) * (90/100)
= 229635

Let the original price be Rs. 100.
New final price = 120 % of (90 % of Rs. 100)
= Rs. (120/100 * 90/100 * 100)
= Rs. 108.
Increase = 8%

It Can be done using a simple formula for percentage :
Decrease in consumption = [% Price increase / (100 + % Price Increase) ] × 100
So , If price of onion rises by 25% =>
Decrease in consumption = [ 25 / (100 + 25) ] × 100
= [ 25 / 125 ] × 100 = 20

Let number of pens sold on tuesday be x given that the percentage increase in the number of pens sold by a trader from Tuesday to Wednesday is same as the percentage decrease in the number of pens sold from Monday to Tuesday.

Percentage increase in sales of pen from tuesday to wednesday = Percentage decrease in sales from monday to tuesday = 20% then on wednesday trader sold 16 more pens than those sold on tuesday.

So number of pens sold on wednesday = x + 16 and this is 20% more than number of pens sold on tuesday
[1 + (20/100) ] * x = x + 16
6x/5 = x + 16
x = 80
So number of pens sold on tuesday x = 80.

Party 2 and 3 Got 12 and 43% Respectively = 55% as a whole.
55% of 16000 = 8800 and Party 1 got 45% Vote = 45% of 16000 = 7200.
Margin of Votes = 8800 – 7200 = 1600

The fruit content in both the fresh fruit and dry fruit is the same.
Given, fresh fruit has 68% water. So remaining 32% is fruit content.
weight of fresh fruits is 100kg Dry fruit has 20% water. So remaining 80% is fruit content.
Let weight if dry fruit be y kg.
fruit % in freshfruit = fruit % in dryfruit
(32/100) * 100 = (80/100 ) * y
we get y = 40 kg.

Let the total vote is x. then 30% of x = (30/100) * x=1200, or x = (1200 * 100) / 30 or x = 4000
Now, 30% of votes already given…so other 70% of x votes = (70/100) * 4000 = 2800 votes.
Now other needed votes = (70 – 30)% = 40% votes.
So 40% votes of x = (40/100) * 4000 = 1600;
Now he have needed only % of votes = (100 * 1600) / 2800 = 160000 / 2800 = 57.14285714%

40,000 * 3/4 * 3/4 * 3/4 = 16875

Paper A : (18/70) * 100 ~= 25.71%
Paper B : (14/30) * 100 ~= 46.66%.
Therefore the solution is Paper B

Let initially there were 100 labour and total work load was 100 units, so each labor’s work = 1 unit.
When there are 33.33% or (100/3) % more labour, total labours = 100 + (100/3) = 400/3
As 400/3 labours has to complete the same work of 100 units, so each labour’s work = 100 / (400/3) = 3/4 unit.
Hence % reduction in the work load of each labour = (1- 3/4) * 100/1 = 100/4 = 25.

Daughter weight is x, infant weight is 60% less than daughter (i.e. 0.4x).
Mother weight is (x + 0.4x + 46).
Total weight = x + 0.4x + (x + 0.4x + 46) = 74.
Solving the eq. x = 10