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		<title>Find the smallest 4 digit number which is divisible by 18, 24, 32 ?</title>
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		<pubDate>Tue, 17 Aug 2021 17:54:58 +0000</pubDate>
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		<guid isPermaLink="false">https://www.wikitechy.com/interview-questions/?p=1845</guid>

					<description><![CDATA[Answer : C. 1152]]></description>
										<content:encoded><![CDATA[<div class="TextHeading">
<div class="hddn">
<p class="color-pink">Find the smallest 4 digit number which is divisible by 18, 24, 32 ?</p>
<div class="row">
<div class="col-sm-6">
<p>A. 1216</p>
</div>
<div class="col-sm-6">
<p>B. 1512</p>
</div>
<div class="col-sm-6">
<p>C. 1152</p>
</div>
<div class="col-sm-6">
<p>D. 1680</p>
</div>
</div>
</div>
</div>
<h3 id="answer-c-1152"><b>Answer : </b>C. 1152</h3>
<div class="subheading">
<h2 id="explanation">Explanation:</h2>
</div>
<div class="Content">
<div class="hddn">
<p>LCM of 18, 24 and 32:<br />
&#8211;&gt; 18 = 2 x 3 x 3<br />
&#8211;&gt; 24 = 2 x 2 x 2 x 3<br />
&#8211;&gt; 32 = 2 x 2 x 2 x 2 x 2<br />
LCM = 2 x 2 x 2 x 2 x 2 x 3 x 3 = 288.</p>
<p>The smallest four digit number that is divisible by 288:<br />
288 x 3 = 864<br />
288 x 4 = 1152</p>
<p>Since 288 is divisible by 18, 24 and 32, 1152 is also divisible by all these numbers. Therefore, 1152 is the smallest four digit number divisible by 18, 24 and 32.</p>
</div>
</div>
]]></content:encoded>
					
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		<title>Find the greatest number which on dividing 1661 and 2045, leaves a remainder of 10 and 13 respectively ?</title>
		<link>https://www.wikitechy.com/interview-questions/lcm-and-hcf/find-the-greatest-number-which-on-dividing-1661-and-2045-leaves-a-remainder-of-10-and-13-respectively/</link>
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		<dc:creator><![CDATA[Editor]]></dc:creator>
		<pubDate>Tue, 17 Aug 2021 17:48:26 +0000</pubDate>
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		<guid isPermaLink="false">https://www.wikitechy.com/interview-questions/?p=1842</guid>

					<description><![CDATA[Answer : B . 127]]></description>
										<content:encoded><![CDATA[<div class="TextHeading">
<div class="hddn">
<p class="color-pink">Find the greatest number which on dividing 1661 and 2045, leaves a remainder of 10 and 13 respectively ?</p>
<div class="row">
<div class="col-sm-6">
<p>A. 91</p>
</div>
<div class="col-sm-6">
<p>B. 127</p>
</div>
<div class="col-sm-6">
<p>C. 137</p>
</div>
<div class="col-sm-6">
<p>D. 140</p>
</div>
</div>
</div>
</div>
<h3 id="answer-b-127"><b>Answer : </b>B . 127</h3>
<div class="subheading">
<h2 id="explanation">Explanation:</h2>
</div>
<div class="Content">
<div class="hddn">
<p>In this type of question, we need to calculate the HCF, trick is,<br />
HCF (1661 – 10) and (2045 -13)<br />
= HCF (1651, 2032)<br />
= 127</p>
</div>
</div>
]]></content:encoded>
					
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		<title>How to find LCM of two Numbers in C ?</title>
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		<pubDate>Mon, 12 Jul 2021 21:04:03 +0000</pubDate>
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					<description><![CDATA[Answer : The LCM of two numbers a and b is the smallest positive integer that is perfectly divisible...]]></description>
										<content:encoded><![CDATA[<h2 id="to-find-lcm-of-two-numbers-in-c" class="color-pink" style="text-align: justify;">To Find LCM of Two Numbers in C</h2>
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<li>The LCM of two numbers a and b is the smallest positive integer that is perfectly divisible by both a and b (without a remainder). For example: The LCM of 72 and 120 is 360.</li>
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<h2 id="sample-code" class="color-blue" style="text-align: justify;">Sample Code</h2>
<div class="code-embed-wrapper"> <div class="code-embed-infos"> </div> <pre class="language-c code-embed-pre line-numbers"  data-start="1" data-line-offset="0"><code class="language-c code-embed-code">#include &lt;stdio.h&gt; <br/>// Recursive function to return gcd of a and b<br/>int gcd(int a, int b)<br/>{<br/>// Everything divides 0<br/>    if (a == 0 || b == 0)<br/>        return 0;<br/>// Base case<br/>    if (a == b)<br/>        return a;<br/>// a is greater<br/>    if (a &gt; b)<br/>        return gcd(a-b, b);<br/>    return gcd(a, b-a);<br/>}<br/>// Function to return LCM of two numbers<br/>int lcm(int a, int b)<br/>{<br/>    return (a*b)/gcd(a, b);<br/>}<br/>// Driver program to test above function<br/>int main()<br/>{<br/>    int a = 10, b = 28;<br/>    printf(&quot;LCM of %d and %d is %d &quot;, a, b, lcm(a, b));<br/>    return 0;<br/>}</code></pre> </div>
<h2 id="output" class="color-blue" style="text-align: justify;">Output</h2>
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<figure class="highlight"><div class="code-embed-wrapper"> <div class="code-embed-infos"> </div> <pre class="language-c code-embed-pre line-numbers"  data-start="1" data-line-offset="0"><code class="language-c code-embed-code">LCM of 10 and 28 is 140</code></pre> </div></figure>
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