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	<title>How many 3-digit numbers can be formed from the digits 2 - Wikitechy</title>
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		<title>How many 3-digit numbers can be formed from the digits 2, 3, 5, 6, 7 and 9, which are divisible by 5 and none of the digits is repeated ?</title>
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		<pubDate>Tue, 17 Aug 2021 20:06:35 +0000</pubDate>
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					<description><![CDATA[Answer : D. 20]]></description>
										<content:encoded><![CDATA[<div class="TextHeading">
<div class="hddn">
<p class="color-pink">How many 3-digit numbers can be formed from the digits 2, 3, 5, 6, 7 and 9, which are divisible by 5 and none of the digits is repeated ?</p>
<div class="row">
<div class="col-sm-6">
<p>A. 5</p>
</div>
<div class="col-sm-6">
<p>B. 10</p>
</div>
<div class="col-sm-6">
<p>C. 15</p>
</div>
<div class="col-sm-6">
<p>D. 20</p>
</div>
</div>
</div>
</div>
<h3 id="answer-d-20"><b>Answer : </b>D. 20</h3>
<div class="subheading">
<h2 id="explanation">Explanation:</h2>
</div>
<div class="Content">
<div class="hddn">
<p>Since each desired number is divisible by 5, so we must have 5 at the unit place. So, there is 1 way of doing it.<br />
The tens place can now be filled by any of the remaining 5 digits (2, 3, 6, 7, 9). So, there are 5 ways of filling the tens place.<br />
The hundreds place can now be filled by any of the remaining 4 digits. So, there are 4 ways of filling it.<br />
Required number of ways = (1 x 5 x 4) = 20.</p>
</div>
</div>
]]></content:encoded>
					
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