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		<title>If 100.3010 = 2, then find the value of log0.125 (125) ?</title>
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		<pubDate>Wed, 18 Aug 2021 01:11:30 +0000</pubDate>
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					<description><![CDATA[Answer : B. – 699 / 301...]]></description>
										<content:encoded><![CDATA[<div class="TextHeading">
<div class="hddn">
<p class="color-purple">If 10<sup>0.3010</sup> = 2, then find the value of log0.125 (125) ?</p>
<div class="row">
<div class="col-sm-6">
<p>A. 699 / 301</p>
</div>
<div class="col-sm-6">
<p>B. – 699 / 301</p>
</div>
<div class="col-sm-6">
<p>C. – 1</p>
</div>
<div class="col-sm-6">
<p>D. – 2</p>
</div>
</div>
</div>
</div>
<h3 id="answer-b-699-301"><b>Answer :</b> B. – 699 / 301&#8230;</h3>
<div class="subheading">
<h2 id="explanation">Explanation:</h2>
</div>
<div class="Content">
<div class="hddn">
<p>10<sup>0.3010</sup> = 2 ,<br />
take log base 10 both sides ,<br />
log<sub>10</sub>10<sup>0.3010</sup> = log<sub>10</sub>2<br />
0.3010 = log<sub>10</sub>2</p>
<p><b>Given :</b><br />
log<sub>0.125</sub>125 = log<sub>125/1000</sub>125<br />
= log<sub>0.5</sub>5 = 1 / log<sub>5</sub>0.5<br />
= 1 / -log<sub>5</sub>2<br />
= -log<sub>10</sub>5 / log<sub>10</sub>2<br />
= -2.321 [ log5 = 0.6989 and log2 = 0.3010]
</div>
</div>
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		<title>The simplified form of log (75/16) &#8211; 2 log (5/9) + log (32/343) is ?</title>
		<link>https://www.wikitechy.com/interview-questions/logarithm/the-simplified-form-of-log-75-16-2-log-5-9-log-32-343-is/</link>
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		<dc:creator><![CDATA[Editor]]></dc:creator>
		<pubDate>Wed, 18 Aug 2021 01:07:53 +0000</pubDate>
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					<description><![CDATA[Answer : A . log 2]]></description>
										<content:encoded><![CDATA[<div class="TextHeading">
<div class="hddn">
<p class="color-pink">The simplified form of log (75/16) &#8211; 2 log (5/9) + log (32/343) is ?</p>
<div class="row">
<div class="col-sm-6">
<p>A . log 2</p>
</div>
<div class="col-sm-6">
<p>B . 2 log 2</p>
</div>
<div class="col-sm-6">
<p>C . log 3</p>
</div>
<div class="col-sm-6">
<p>D . log 5</p>
</div>
</div>
</div>
</div>
<h3 id="answer-a-log-2"><b>Answer : </b>A . log 2</h3>
<div class="subheading">
<h2 id="explanation">Explanation:</h2>
</div>
<div class="Content">
<div class="hddn">
<p><b>Given:</b><br />
= log75/16 – 2 log5/9 + log32/343<br />
= log [(25 x 3)/(4 x 4)] – log (25/81) + log [(16 x 2)/(81 x 3)]
= log(25 x 3) – log ( 4 x 4 ) – log(25) + log81 + log(16 x 2) &#8211; log (81 x 3)<br />
= log 25 + log 3 – log 16 – log 25 + log 81 + log 16 + log 2 – log 81 – log 3<br />
= log 2</p>
</div>
</div>
]]></content:encoded>
					
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