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	<item>
		<title>If log 125 / log 5 = x, then x is equal to ?</title>
		<link>https://www.wikitechy.com/interview-questions/logarithm/if-log-125-log-5-x-then-x-is-equal-to/</link>
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		<dc:creator><![CDATA[Editor]]></dc:creator>
		<pubDate>Wed, 18 Aug 2021 01:18:49 +0000</pubDate>
				<category><![CDATA[Logarithm]]></category>
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		<guid isPermaLink="false">https://www.wikitechy.com/interview-questions/?p=2013</guid>

					<description><![CDATA[Answer : B. 3]]></description>
										<content:encoded><![CDATA[<div class="TextHeading">
<div class="hddn">
<p class="color-pink">If log 125 / log 5 = x, then x is equal to ?</p>
<div class="row">
<div class="col-sm-6">
<p>A. 2</p>
</div>
<div class="col-sm-6">
<p>B. 3</p>
</div>
<div class="col-sm-6">
<p>C. 4</p>
</div>
<div class="col-sm-6">
<p>D. 1/2</p>
</div>
</div>
</div>
</div>
<h3 id="answer-b-3"><b>Answer : </b>B. 3</h3>
<div class="subheading">
<h2 id="explanation">Explanation :</h2>
</div>
<div class="Content">
<div class="hddn">
<p>log 125 / log 5 = x.<br />
log 5<sup>3</sup> / log 5 = x<br />
x = 3 log5 / log5<br />
= 3</p>
</div>
</div>
]]></content:encoded>
					
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			</item>
		<item>
		<title>If 100.3010 = 2, then find the value of log0.125 (125) ?</title>
		<link>https://www.wikitechy.com/interview-questions/logarithm/if-100-3010-2-then-find-the-value-of-log0-125-125/</link>
					<comments>https://www.wikitechy.com/interview-questions/logarithm/if-100-3010-2-then-find-the-value-of-log0-125-125/#respond</comments>
		
		<dc:creator><![CDATA[Editor]]></dc:creator>
		<pubDate>Wed, 18 Aug 2021 01:11:30 +0000</pubDate>
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		<guid isPermaLink="false">https://www.wikitechy.com/interview-questions/?p=2010</guid>

					<description><![CDATA[Answer : B. – 699 / 301...]]></description>
										<content:encoded><![CDATA[<div class="TextHeading">
<div class="hddn">
<p class="color-purple">If 10<sup>0.3010</sup> = 2, then find the value of log0.125 (125) ?</p>
<div class="row">
<div class="col-sm-6">
<p>A. 699 / 301</p>
</div>
<div class="col-sm-6">
<p>B. – 699 / 301</p>
</div>
<div class="col-sm-6">
<p>C. – 1</p>
</div>
<div class="col-sm-6">
<p>D. – 2</p>
</div>
</div>
</div>
</div>
<h3 id="answer-b-699-301"><b>Answer :</b> B. – 699 / 301&#8230;</h3>
<div class="subheading">
<h2 id="explanation">Explanation:</h2>
</div>
<div class="Content">
<div class="hddn">
<p>10<sup>0.3010</sup> = 2 ,<br />
take log base 10 both sides ,<br />
log<sub>10</sub>10<sup>0.3010</sup> = log<sub>10</sub>2<br />
0.3010 = log<sub>10</sub>2</p>
<p><b>Given :</b><br />
log<sub>0.125</sub>125 = log<sub>125/1000</sub>125<br />
= log<sub>0.5</sub>5 = 1 / log<sub>5</sub>0.5<br />
= 1 / -log<sub>5</sub>2<br />
= -log<sub>10</sub>5 / log<sub>10</sub>2<br />
= -2.321 [ log5 = 0.6989 and log2 = 0.3010]
</div>
</div>
]]></content:encoded>
					
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		<item>
		<title>The value of log 9/8 &#8211; log 27/32 + log 3/4 is ?</title>
		<link>https://www.wikitechy.com/interview-questions/logarithm/the-value-of-log-9-8-log-27-32-log-3-4-is/</link>
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		<dc:creator><![CDATA[Editor]]></dc:creator>
		<pubDate>Wed, 18 Aug 2021 01:05:50 +0000</pubDate>
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		<guid isPermaLink="false">https://www.wikitechy.com/interview-questions/?p=2007</guid>

					<description><![CDATA[Answer : A . 0]]></description>
										<content:encoded><![CDATA[<div class="TextHeading">
<div class="hddn">
<p class="color-pink">The value of log 9/8 &#8211; log 27/32 + log 3/4 is ?</p>
<div class="row">
<div class="col-sm-6">
<p>A . 0</p>
</div>
<div class="col-sm-6">
<p>B . 1</p>
</div>
<div class="col-sm-6">
<p>C . 2</p>
</div>
<div class="col-sm-6">
<p>D . 3</p>
</div>
</div>
<h3 id="answer-a-0"><b>Answer : </b>A . 0</h3>
</div>
</div>
<div class="subheading">
<h2 id="explanation">Explanation:</h2>
</div>
<div class="Content">
<div class="hddn">
<p><b>Given:</b><br />
= log [ { (9 / 8) / (27 / 32) } x 3 / 4) ]
= log [ (9 / 8) x (3 / 4) x (32 / 27) ]
= log 1<br />
= 0</p>
</div>
</div>
]]></content:encoded>
					
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