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		<title>log10(10) + log10(100) + log10(1000) + log10(10000) + log10(100000) is equal to ?</title>
		<link>https://www.wikitechy.com/interview-questions/logarithm/log1010-log10100-log101000-log1010000-log10100000-is-equal-to/</link>
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		<dc:creator><![CDATA[Editor]]></dc:creator>
		<pubDate>Wed, 18 Aug 2021 01:14:48 +0000</pubDate>
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					<description><![CDATA[Answer : A. 15]]></description>
										<content:encoded><![CDATA[<div class="TextHeading">
<div class="hddn">
<p class="color-pink">log<sub>10</sub>(10) + log<sub>10</sub>(100) + log<sub>10</sub>(1000) + log<sub>10</sub>(10000) + log<sub>10</sub>(100000) is equal to ?</p>
<div class="row">
<div class="col-sm-6">
<p>A. 15</p>
</div>
<div class="col-sm-6">
<p>B. log 11111</p>
</div>
<div class="col-sm-6">
<p>C. log10 (1111)</p>
</div>
<div class="col-sm-6">
<p>D. 14 log10 (100)</p>
</div>
</div>
</div>
</div>
<h3 id="answer-a-15"><b>Answer : </b>A. 15</h3>
<div class="subheading">
<h2 id="explanation">Explanation :</h2>
</div>
<div class="Content">
<div class="hddn">
<p>Here are some values to base ten represented as logarithms :</p>
</div>
</div>
<table class="table-bordered table-striped table table-responsive">
<tbody>
<tr>
<th>Value</th>
<th>As 10 raised to a power</th>
<th>Log to base 10</th>
</tr>
<tr>
<td class="text-leftalign">1</td>
<td class="text-leftalign">10 <sup>0</sup></td>
<td class="text-leftalign">0</td>
</tr>
<tr>
<td class="text-leftalign">10</td>
<td class="text-leftalign">10 <sup>1</sup></td>
<td class="text-leftalign">1</td>
</tr>
<tr>
<td class="text-leftalign">100</td>
<td class="text-leftalign">10 <sup>2</sup></td>
<td class="text-leftalign">2</td>
</tr>
<tr>
<td class="text-leftalign">1000</td>
<td class="text-leftalign">10 <sup>3</sup></td>
<td class="text-leftalign">3</td>
</tr>
<tr>
<td class="text-leftalign">10000</td>
<td class="text-leftalign">10 <sup>4</sup></td>
<td class="text-leftalign">4</td>
</tr>
<tr>
<td class="text-leftalign">100000</td>
<td class="text-leftalign">10 <sup>5</sup></td>
<td class="text-leftalign">5</td>
</tr>
</tbody>
</table>
<p>1 + 2 + 3 + 4 + 5 = 15</p>
]]></content:encoded>
					
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			</item>
		<item>
		<title>If 100.3010 = 2, then find the value of log0.125 (125) ?</title>
		<link>https://www.wikitechy.com/interview-questions/logarithm/if-100-3010-2-then-find-the-value-of-log0-125-125/</link>
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		<dc:creator><![CDATA[Editor]]></dc:creator>
		<pubDate>Wed, 18 Aug 2021 01:11:30 +0000</pubDate>
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		<guid isPermaLink="false">https://www.wikitechy.com/interview-questions/?p=2010</guid>

					<description><![CDATA[Answer : B. – 699 / 301...]]></description>
										<content:encoded><![CDATA[<div class="TextHeading">
<div class="hddn">
<p class="color-purple">If 10<sup>0.3010</sup> = 2, then find the value of log0.125 (125) ?</p>
<div class="row">
<div class="col-sm-6">
<p>A. 699 / 301</p>
</div>
<div class="col-sm-6">
<p>B. – 699 / 301</p>
</div>
<div class="col-sm-6">
<p>C. – 1</p>
</div>
<div class="col-sm-6">
<p>D. – 2</p>
</div>
</div>
</div>
</div>
<h3 id="answer-b-699-301"><b>Answer :</b> B. – 699 / 301&#8230;</h3>
<div class="subheading">
<h2 id="explanation">Explanation:</h2>
</div>
<div class="Content">
<div class="hddn">
<p>10<sup>0.3010</sup> = 2 ,<br />
take log base 10 both sides ,<br />
log<sub>10</sub>10<sup>0.3010</sup> = log<sub>10</sub>2<br />
0.3010 = log<sub>10</sub>2</p>
<p><b>Given :</b><br />
log<sub>0.125</sub>125 = log<sub>125/1000</sub>125<br />
= log<sub>0.5</sub>5 = 1 / log<sub>5</sub>0.5<br />
= 1 / -log<sub>5</sub>2<br />
= -log<sub>10</sub>5 / log<sub>10</sub>2<br />
= -2.321 [ log5 = 0.6989 and log2 = 0.3010]
</div>
</div>
]]></content:encoded>
					
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		<title>Find the value of log (a2 / bc) + log (b2 / ac) + log (c2 / ab) ?</title>
		<link>https://www.wikitechy.com/interview-questions/logarithm/find-the-value-of-log-a2-bc-log-b2-ac-log-c2-ab/</link>
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		<dc:creator><![CDATA[Editor]]></dc:creator>
		<pubDate>Wed, 18 Aug 2021 01:09:46 +0000</pubDate>
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		<guid isPermaLink="false">https://www.wikitechy.com/interview-questions/?p=2009</guid>

					<description><![CDATA[Answer : A. 0...]]></description>
										<content:encoded><![CDATA[<div class="TextHeading">
<div class="hddn">
<p class="color-pink">Find the value of log (a<sup>2</sup> / bc) + log (b<sup>2</sup> / ac) + log (c<sup>2</sup> / ab) ?</p>
<div class="row">
<div class="col-sm-6">
<p>A. 0</p>
</div>
<div class="col-sm-6">
<p>B. 1</p>
</div>
<div class="col-sm-6">
<p>C. abc</p>
</div>
<div class="col-sm-6">
<p>D. ab<sup>2</sup>c<sup>2</sup></p>
</div>
</div>
</div>
</div>
<h3 id="answer-a-0"><b>Answer : </b>A. 0&#8230;</h3>
<div class="subheading">
<h2 id="explanation">Explanation:</h2>
</div>
<div class="Content">
<div class="hddn">
<p>logX + logY = log (XY)<br />
= log (a<sup>2</sup>/bc) + log (b<sup>2</sup>/ac) + log (c<sup>2</sup>/ab)<br />
= log (a<sup>2</sup> b<sup>2</sup> c<sup>2</sup> / bcacab)<br />
= log (a<sup>2</sup> b<sup>2</sup>c<sup>2</sup> / a<sup>2</sup>b<sup>2</sup>c<sup>2</sup>)<br />
= log 1<br />
= 0</p>
</div>
</div>
]]></content:encoded>
					
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		<title>The simplified form of log (75/16) &#8211; 2 log (5/9) + log (32/343) is ?</title>
		<link>https://www.wikitechy.com/interview-questions/logarithm/the-simplified-form-of-log-75-16-2-log-5-9-log-32-343-is/</link>
					<comments>https://www.wikitechy.com/interview-questions/logarithm/the-simplified-form-of-log-75-16-2-log-5-9-log-32-343-is/#respond</comments>
		
		<dc:creator><![CDATA[Editor]]></dc:creator>
		<pubDate>Wed, 18 Aug 2021 01:07:53 +0000</pubDate>
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		<guid isPermaLink="false">https://www.wikitechy.com/interview-questions/?p=2008</guid>

					<description><![CDATA[Answer : A . log 2]]></description>
										<content:encoded><![CDATA[<div class="TextHeading">
<div class="hddn">
<p class="color-pink">The simplified form of log (75/16) &#8211; 2 log (5/9) + log (32/343) is ?</p>
<div class="row">
<div class="col-sm-6">
<p>A . log 2</p>
</div>
<div class="col-sm-6">
<p>B . 2 log 2</p>
</div>
<div class="col-sm-6">
<p>C . log 3</p>
</div>
<div class="col-sm-6">
<p>D . log 5</p>
</div>
</div>
</div>
</div>
<h3 id="answer-a-log-2"><b>Answer : </b>A . log 2</h3>
<div class="subheading">
<h2 id="explanation">Explanation:</h2>
</div>
<div class="Content">
<div class="hddn">
<p><b>Given:</b><br />
= log75/16 – 2 log5/9 + log32/343<br />
= log [(25 x 3)/(4 x 4)] – log (25/81) + log [(16 x 2)/(81 x 3)]
= log(25 x 3) – log ( 4 x 4 ) – log(25) + log81 + log(16 x 2) &#8211; log (81 x 3)<br />
= log 25 + log 3 – log 16 – log 25 + log 81 + log 16 + log 2 – log 81 – log 3<br />
= log 2</p>
</div>
</div>
]]></content:encoded>
					
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		<title>What is the value of log(ab2) &#8211; log(ac) + log(abc4) &#8211; 3log(bc) ?</title>
		<link>https://www.wikitechy.com/interview-questions/logarithm/what-is-the-value-of-logab2-logac-logabc4-3logbc/</link>
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		<dc:creator><![CDATA[Editor]]></dc:creator>
		<pubDate>Wed, 18 Aug 2021 01:04:45 +0000</pubDate>
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					<description><![CDATA[Answer : D. 1...]]></description>
										<content:encoded><![CDATA[<div class="TextHeading">
<div class="hddn">
<p class="color-pink">What is the value of log(ab<sup>2</sup>) &#8211; log(ac) + log(abc<sup>4</sup>) &#8211; 3log(bc) ?</p>
<div class="row">
<div class="col-sm-6">
<p>A. 2</p>
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<div class="col-sm-6">
<p>B. 0</p>
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<div class="col-sm-6">
<p>C. -2</p>
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<div class="col-sm-6">
<p>D. 1</p>
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</div>
</div>
</div>
<h3 id="answer-d-1"><b>Answer : </b>D. 1&#8230;</h3>
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<h2 id="explanation">Explanation:</h2>
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<div class="Content">
<div class="hddn">
<p>log(ab<sup>2</sup>) – log(ac) + log abc<sup>4</sup> – 3log(bc)<br />
= log ab<sup>2</sup> – logac + log abc<sup>4</sup> – log b<sup>3</sup>c<sup>3</sup><br />
= log<sub>a</sub> (ab<sup>2</sup>/ac) x (abc<sup>4</sup>/b<sup>3</sup>c<sup>3</sup>)<br />
= log<sub>a</sub>a = 1</p>
</div>
</div>
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