Syntax

namespace namespace_name  
{  
     //body of namespace;  
}  

Syntax of accessing the namespace variable

namespace_name::member_name; 

Sample code

 using namespace std;  
namespace addition  
{  
    int a=5;  
    int b=5;  
    int add()  
    {  
        return(a+b);  
    }  
}  
  
int main() {  
int result;  
result=addition::add();  
cout<<result;  
return 0;  
      }  

Output

• If python interpreter runs solely without any user-defined modules, methods, classes, etc. Some functions like print (), id () is always present, these are built-in namespaces.
• If user creates a module, a global namespace gets created, later the creation of local functions creates the local namespace.
• The global namespace encompasses the local namespace and built-in namespace encompasses global namespace.
• If scope of an object ends, the lifetime of that namespace comes to an end, so the lifetime of a namespace depends upon the scope of objects.
• Hence there is no possible to access the inner namespace’s objects from an outer namespace.

Sample Code

# Python program processing
# global variable
 
count = 10
def some_method ():
    global count
    count = count + 10
    print(count)
some_method ()

Output