Wipro Interview Questions for Freshers | Wipro Fresher Interview Questions - Wikitechy https://www.wikitechy.com/interview-questions/tag/wipro-interview-questions-for-freshers-wipro-fresher-interview-questions/ Interview Questions Fri, 17 Sep 2021 11:17:03 +0000 en-US hourly 1 https://wordpress.org/?v=6.9 https://www.wikitechy.com/interview-questions/wp-content/uploads/2025/10/cropped-wikitechy-icon-32x32.png Wipro Interview Questions for Freshers | Wipro Fresher Interview Questions - Wikitechy https://www.wikitechy.com/interview-questions/tag/wipro-interview-questions-for-freshers-wipro-fresher-interview-questions/ 32 32 A boat covers a distance of 30 km downstream in 2 hours while it takes 6 hours to cover the same distance upstream. What is the speed of the boat in km/hr ? https://www.wikitechy.com/interview-questions/boats-and-streams/a-boat-covers-a-distance-of-30-km-downstream-in-2-hours-while-it-takes-6-hours-to-cover-the-same-distance-upstream-what-is-the-speed-of-the-boat-in-km-hr/ https://www.wikitechy.com/interview-questions/boats-and-streams/a-boat-covers-a-distance-of-30-km-downstream-in-2-hours-while-it-takes-6-hours-to-cover-the-same-distance-upstream-what-is-the-speed-of-the-boat-in-km-hr/#respond Wed, 18 Aug 2021 02:44:04 +0000 https://www.wikitechy.com/interview-questions/?p=2078

A boat covers a distance of 30 km downstream in 2 hours while it takes 6 hours to cover the same distance upstream. What is the speed of the boat in km/hr ?

A. 5

B. 7.5

C. 10

D. 12

Answer : C. 10

Explanation :

  • Speed of boat downstream
    = Distance covered / Time taken
    = 30/2
    = 15 km/h
  • Now, speed of boat upstream
    = Distance covered / Time taken
    = 30/6
    = 5 km/h
  • Now, speed of boat = (Speed downstream + Speed upstream)/2
    = (15 + 5)/2
    = 20/2
    = 10 km/h.
]]> https://www.wikitechy.com/interview-questions/boats-and-streams/a-boat-covers-a-distance-of-30-km-downstream-in-2-hours-while-it-takes-6-hours-to-cover-the-same-distance-upstream-what-is-the-speed-of-the-boat-in-km-hr/feed/ 0 A motorboat whose speed is 15 km/hr in still water goes 30km downstream and comes back in four and a half hours. The speed of the stream is ? https://www.wikitechy.com/interview-questions/boats-and-streams/a-motorboat-whose-speed-is-15-km-hr-in-still-water-goes-30km-downstream-and-comes-back-in-four-and-a-half-hours-the-speed-of-the-stream-is/ https://www.wikitechy.com/interview-questions/boats-and-streams/a-motorboat-whose-speed-is-15-km-hr-in-still-water-goes-30km-downstream-and-comes-back-in-four-and-a-half-hours-the-speed-of-the-stream-is/#respond Wed, 18 Aug 2021 02:39:49 +0000 https://www.wikitechy.com/interview-questions/?p=2075

A motorboat whose speed is 15 km/hr in still water goes 30km downstream and comes back in four and a half hours. The speed of the stream is ?

A. 4.5 km/hr

B. 6 km/hr

C. 7 km/hr

D. 5 km/hr

Answer : D. 5 km/hr

Explanation :

Let the speed of the stream be x km/hr. Then,
Speed downstream = (15 + x) km/hr
Speed upstream = (15 – x) km/hr

We know from question that it took 4(1/2)hrs to travel back to same point.
So, (30/15 + x) + (30/15 − x) = 4(1/2)
=> 900/225 − x2 = 9/2
=> 9x2 = 225
=> x = 5km/hr.

]]> https://www.wikitechy.com/interview-questions/boats-and-streams/a-motorboat-whose-speed-is-15-km-hr-in-still-water-goes-30km-downstream-and-comes-back-in-four-and-a-half-hours-the-speed-of-the-stream-is/feed/ 0 If the simple interest on a certain sum of money is 4/25 of the sum and the rate percent equals the number years, then the rate of interest per annum is ? https://www.wikitechy.com/interview-questions/simple-interest/if-the-simple-interest-on-a-certain-sum-of-money-is-4-25-of-the-sum-and-the-rate-percent-equals-the-number-years-then-the-rate-of-interest-per-annum-is/ https://www.wikitechy.com/interview-questions/simple-interest/if-the-simple-interest-on-a-certain-sum-of-money-is-4-25-of-the-sum-and-the-rate-percent-equals-the-number-years-then-the-rate-of-interest-per-annum-is/#respond Wed, 18 Aug 2021 02:28:06 +0000 https://www.wikitechy.com/interview-questions/?p=2063

If the simple interest on a certain sum of money is 4/25 of the sum and the rate percent equals the number years, then the rate of interest per annum is ?

A. 4 %

B. 5 %

C. 8 %

D. 10 %

Answer : A. 4 %…

Explanation :

Let the principal be Rs.x, then the simple interest (I) = (4 / 25 )x.
The rate of interest per annum be r% then time (T) = r years
R = ( 100 * I ) / ( P * T )
r = ( 100 * ( 4/25 ) x ) / ( x * r )
r2 = 400 / 25
r = 20 / 5
= 4 %

]]> https://www.wikitechy.com/interview-questions/simple-interest/if-the-simple-interest-on-a-certain-sum-of-money-is-4-25-of-the-sum-and-the-rate-percent-equals-the-number-years-then-the-rate-of-interest-per-annum-is/feed/ 0 A certain sum of money amounts to Rs.1300 in 2 years and to Rs. 1525 in 3.5 years. Find the sum and the rate of interest ? https://www.wikitechy.com/interview-questions/simple-interest/a-certain-sum-of-money-amounts-to-rs-1300-in-2-years-and-to-rs-1525-in-3-5-years-find-the-sum-and-the-rate-of-interest/ https://www.wikitechy.com/interview-questions/simple-interest/a-certain-sum-of-money-amounts-to-rs-1300-in-2-years-and-to-rs-1525-in-3-5-years-find-the-sum-and-the-rate-of-interest/#respond Wed, 18 Aug 2021 02:26:10 +0000 https://www.wikitechy.com/interview-questions/?p=2062

A certain sum of money amounts to Rs.1300 in 2 years and to Rs. 1525 in 3.5 years. Find the sum and the rate of interest ?

A. Rs 850 , 10%

B. Rs 900, 12%

C. Rs 800, 13%

D. Rs 1000,15%

Answer : D. Rs 1000, 15%…

Explanation :

1525 – 1300 = 225 for 1.5 yrs (3.5 – 2)
So for one yr 225 / 1.5 = 150
then for 2 yrs interest is 150 + 150 = 300
Then principal 1300 – 300 = 1000.
Now 150 / 1000 * 100 = 15%

]]> https://www.wikitechy.com/interview-questions/simple-interest/a-certain-sum-of-money-amounts-to-rs-1300-in-2-years-and-to-rs-1525-in-3-5-years-find-the-sum-and-the-rate-of-interest/feed/ 0 In a dairy farm, 40 cows eat 40 bags of husk in 40 days. In how many days one cow will eat one bag of husk ? https://www.wikitechy.com/interview-questions/chain-rule/in-a-dairy-farm-40-cows-eat-40-bags-of-husk-in-40-days-in-how-many-days-one-cow-will-eat-one-bag-of-husk/ https://www.wikitechy.com/interview-questions/chain-rule/in-a-dairy-farm-40-cows-eat-40-bags-of-husk-in-40-days-in-how-many-days-one-cow-will-eat-one-bag-of-husk/#respond Tue, 17 Aug 2021 21:50:57 +0000 https://www.wikitechy.com/interview-questions/?p=1976

In a dairy farm, 40 cows eat 40 bags of husk in 40 days. In how many days one cow will eat one bag of husk ?

A. 1

B. 1/40

C. 40

D. 80

Answer : C. 40

Explanation:

Assume that in x days, one cow will eat one bag of husk.
More cows, less days (Indirect proportion)
More bags, more days (Direct proportion)
Hence we can write as

In a dairy farm, 40 cows eat 40 bags of husk
    • 1 x 40 x x = 40 x 1 x 40
    x = 40.
]]> https://www.wikitechy.com/interview-questions/chain-rule/in-a-dairy-farm-40-cows-eat-40-bags-of-husk-in-40-days-in-how-many-days-one-cow-will-eat-one-bag-of-husk/feed/ 0 A man sitting on a train travelling at the rate of 50 km/hr observes that it takes 9 sec for goods train travelling in the opposite direction to pass him. If the goods train is 187.5m long. Find its speed ? https://www.wikitechy.com/interview-questions/time-and-distance/a-man-sitting-on-a-train-travelling-at-the-rate-of-50-km-hr-observes-that-it-takes-9-sec-for-goods-train-travelling-in-the-opposite-direction-to-pass-him-if-the-goods-train-is-187-5m-long-find-its-s/ https://www.wikitechy.com/interview-questions/time-and-distance/a-man-sitting-on-a-train-travelling-at-the-rate-of-50-km-hr-observes-that-it-takes-9-sec-for-goods-train-travelling-in-the-opposite-direction-to-pass-him-if-the-goods-train-is-187-5m-long-find-its-s/#respond Tue, 17 Aug 2021 21:35:54 +0000 https://www.wikitechy.com/interview-questions/?p=1968

A man sitting on a train travelling at the rate of 50 km/hr observes that it takes 9 sec for goods train travelling in the opposite direction to pass him. If the goods train is 187.5m long. Find its speed ?

A. 40 km/hr

B. 30 km/hr

C. 24 km/hr

D. 25 km/hr

Answer : C. 24 km/hr

Explanation :

Let the speed of goods train be x km/hr.
Then, (50 + x) * ( 5 / 18 ) = 187.5 / 9
⇒ x = 25 km/hr.

]]> https://www.wikitechy.com/interview-questions/time-and-distance/a-man-sitting-on-a-train-travelling-at-the-rate-of-50-km-hr-observes-that-it-takes-9-sec-for-goods-train-travelling-in-the-opposite-direction-to-pass-him-if-the-goods-train-is-187-5m-long-find-its-s/feed/ 0 A cyclist drove one kilometre, with the wind in his back, in three minutes and drove the same way back, against the wind in four minutes. If we assume that the cyclist always puts constant force on the pedals, how much time would it take him to drive one kilometre without wind ? https://www.wikitechy.com/interview-questions/time-and-distance/a-cyclist-drove-one-kilometre-with-the-wind-in-his-back-in-three-minutes-and-drove-the-same-way-back-against-the-wind-in-four-minutes-if-we-assume-that-the-cyclist-always-puts-constant-force-on-th/ https://www.wikitechy.com/interview-questions/time-and-distance/a-cyclist-drove-one-kilometre-with-the-wind-in-his-back-in-three-minutes-and-drove-the-same-way-back-against-the-wind-in-four-minutes-if-we-assume-that-the-cyclist-always-puts-constant-force-on-th/#respond Tue, 17 Aug 2021 21:34:46 +0000 https://www.wikitechy.com/interview-questions/?p=1967

A cyclist drove one kilometre, with the wind in his back, in three minutes and drove the same way back, against the wind in four minutes. If we assume that the cyclist always puts constant force on the pedals, how much time would it take him to drive one kilometre without wind ?

A. 7/3 min

B. 24/7 min

C. 17/7 min

D. 43/12 min

Answer : B. 24/7 min

Explanation :

  • Let the speed of the cyclist be ‘x’ km/h and wind be ‘y’ km/h.
    1 / (x + y) = 3/60
    ⇒ x + y = 20 ——–> (i)
    And, 1 / (x − y) = 4/60
    ⇒ x − y = 15 ——–> (ii)
  • On solving both the equations we get:
    x = 35/2
    y = 5/2
  • Now, time taken by cyclist without wind:
    = 2/35 × 60
    = 24/7 min
]]> https://www.wikitechy.com/interview-questions/time-and-distance/a-cyclist-drove-one-kilometre-with-the-wind-in-his-back-in-three-minutes-and-drove-the-same-way-back-against-the-wind-in-four-minutes-if-we-assume-that-the-cyclist-always-puts-constant-force-on-th/feed/ 0 A car travels first half distance between two places with a speed of 40 km/hr and rest of the half distance with a speed of 60 km/hr. The average speed of the car is ? https://www.wikitechy.com/interview-questions/time-and-distance/a-car-travels-first-half-distance-between-two-places-with-a-speed-of-40-km-hr-and-rest-of-the-half-distance-with-a-speed-of-60-km-hr-the-average-speed-of-the-car-is/ https://www.wikitechy.com/interview-questions/time-and-distance/a-car-travels-first-half-distance-between-two-places-with-a-speed-of-40-km-hr-and-rest-of-the-half-distance-with-a-speed-of-60-km-hr-the-average-speed-of-the-car-is/#respond Tue, 17 Aug 2021 21:33:17 +0000 https://www.wikitechy.com/interview-questions/?p=1966

A car travels first half distance between two places with a speed of 40 km/hr and rest of the half distance with a speed of 60 km/hr. The average speed of the car is ?

A. 48 km/hr

B. 37 km/hr

C. 44 km/hr

D. 45 km/hr

Answer : A. 48 km/hr

Explanation :

Let the total distance covered be S km.
Total time taken= S / (2 × 40) + S / (2 × 60)
= 5S / 240 hr
Average speed = S × ( 240/ 5S )
= 48 km/hr

]]> https://www.wikitechy.com/interview-questions/time-and-distance/a-car-travels-first-half-distance-between-two-places-with-a-speed-of-40-km-hr-and-rest-of-the-half-distance-with-a-speed-of-60-km-hr-the-average-speed-of-the-car-is/feed/ 0 A man can row 4.5 km/hr in still water and he finds that it takes him twice as long to row up as to row down the river. Find the rate of the stream ? https://www.wikitechy.com/interview-questions/time-and-distance/a-man-can-row-4-5-km-hr-in-still-water-and-he-finds-that-it-takes-him-twice-as-long-to-row-up-as-to-row-down-the-river-find-the-rate-of-the-stream/ https://www.wikitechy.com/interview-questions/time-and-distance/a-man-can-row-4-5-km-hr-in-still-water-and-he-finds-that-it-takes-him-twice-as-long-to-row-up-as-to-row-down-the-river-find-the-rate-of-the-stream/#respond Tue, 17 Aug 2021 21:27:35 +0000 https://www.wikitechy.com/interview-questions/?p=1965

A man can row 4.5 km/hr in still water and he finds that it takes him twice as long to row up as to row down the river. Find the rate of the stream ?

A. 2 km/hr

B. 2.5 km/hr

C. 1.5 km/hr

D. 1.75 km/hr

Answer : C. 1.5 km/hrs

Explanation :

Let the speed of the current be x km/hr.
Upward speed = (4.5 + x) km/hr
Downward speed = (4.5 − x) km/hr.
Let distance travelled be y, then
y / (4.5 − x) = 2y / (4.5 + x)
x = 1.5 km/hr

]]> https://www.wikitechy.com/interview-questions/time-and-distance/a-man-can-row-4-5-km-hr-in-still-water-and-he-finds-that-it-takes-him-twice-as-long-to-row-up-as-to-row-down-the-river-find-the-rate-of-the-stream/feed/ 0 Length of the train is 170 meters and speed of the train is 63 km/hour. This train can pass a bridge in 30 seconds, then find the length of the bridge ? https://www.wikitechy.com/interview-questions/problems-on-trains/length-of-the-train-is-170-meters-and-speed-of-the-train-is-63-km-hour-this-train-can-pass-a-bridge-in-30-seconds-then-find-the-length-of-the-bridge/ https://www.wikitechy.com/interview-questions/problems-on-trains/length-of-the-train-is-170-meters-and-speed-of-the-train-is-63-km-hour-this-train-can-pass-a-bridge-in-30-seconds-then-find-the-length-of-the-bridge/#respond Tue, 17 Aug 2021 15:14:40 +0000 https://www.wikitechy.com/interview-questions/?p=1800

Length of the train is 170 meters and speed of the train is 63 km/hour. This train can pass a bridge in 30 seconds, then find the length of the bridge ?

A. 355 mtrs

B. 325 mtrs

C. 365 mtrs

D. 312 mtrs

Answer : A. 355 mtrs

Explanation :

Given speed = 63 km/hr = 63 × 5/18 = 35/2 m/s
Let the length of the bridge = x mts
Given time taken to cover the distance of (170 + x)mts is 30 sec.
We know speed = distance/time
35 / 2 = ( 170 + x ) / 30
x = 355 mts.

]]> https://www.wikitechy.com/interview-questions/problems-on-trains/length-of-the-train-is-170-meters-and-speed-of-the-train-is-63-km-hour-this-train-can-pass-a-bridge-in-30-seconds-then-find-the-length-of-the-bridge/feed/ 0 A train speed past a pole in 15 seconds and a platform 100 m long in 25 seconds. Its length is ? https://www.wikitechy.com/interview-questions/problems-on-trains/a-train-speed-past-a-pole-in-15-seconds-and-a-platform-100-m-long-in-25-seconds-its-length-is/ https://www.wikitechy.com/interview-questions/problems-on-trains/a-train-speed-past-a-pole-in-15-seconds-and-a-platform-100-m-long-in-25-seconds-its-length-is/#respond Tue, 17 Aug 2021 15:12:56 +0000 https://www.wikitechy.com/interview-questions/?p=1799

A train speed past a pole in 15 seconds and a platform 100 m long in 25 seconds. Its length is ?

A. 50 m

B. 150 m

C. 200 m

D. None of these

Answer : B. 150 m

Explanation :

Let the length of the train be x metres and its speed by y m/sec.
Then, x / y = 15
=> y = x / 15
(x + 100) / 25 = x / 15
=> 15(x + 100) = 25x
=> 15x + 1500 = 25x
=> 1500 = 10x
=> x = 150 m.

]]> https://www.wikitechy.com/interview-questions/problems-on-trains/a-train-speed-past-a-pole-in-15-seconds-and-a-platform-100-m-long-in-25-seconds-its-length-is/feed/ 0 Two trains of equal length, running in opposite directions, pass a pole in 18 and 12 seconds. The trains will cross each other in ? https://www.wikitechy.com/interview-questions/problems-on-trains/two-trains-of-equal-length-running-in-opposite-directions-pass-a-pole-in-18-and-12-seconds-the-trains-will-cross-each-other-in/ https://www.wikitechy.com/interview-questions/problems-on-trains/two-trains-of-equal-length-running-in-opposite-directions-pass-a-pole-in-18-and-12-seconds-the-trains-will-cross-each-other-in/#respond Tue, 17 Aug 2021 15:10:18 +0000 https://www.wikitechy.com/interview-questions/?p=1798

Two trains of equal length, running in opposite directions, pass a pole in 18 and 12 seconds. The trains will cross each other in ?

A. 14.4 sec

B. 15.5 sec

C. 18.8 sec

D. 20.2 sec

Answer : A. 14.4 sec

Explanation :

Let length of each train be x meter.
Then, speed of 1st train = x/18 m/sec
Speed of 2nd train = x/12 m/sec

Now, When both trains cross each other, time taken
= [ 2x/((x / 18 ) + (x / 12)) ] = 2x / [(2x + 3x) / 36] = 2x * 36 / 5x
= 72 / 5
= 14.4 seconds.

]]> https://www.wikitechy.com/interview-questions/problems-on-trains/two-trains-of-equal-length-running-in-opposite-directions-pass-a-pole-in-18-and-12-seconds-the-trains-will-cross-each-other-in/feed/ 0 A train of length 110 meters is running at a speed of 60 kmph. In what time, it will pass a man who is running at 6 kmph in the direction opposite to that in which the train is going ? https://www.wikitechy.com/interview-questions/problems-on-trains/a-train-of-length-110-meters-is-running-at-a-speed-of-60-kmph-in-what-time-it-will-pass-a-man-who-is-running-at-6-kmph-in-the-direction-opposite-to-that-in-which-the-train-is-going/ https://www.wikitechy.com/interview-questions/problems-on-trains/a-train-of-length-110-meters-is-running-at-a-speed-of-60-kmph-in-what-time-it-will-pass-a-man-who-is-running-at-6-kmph-in-the-direction-opposite-to-that-in-which-the-train-is-going/#respond Tue, 17 Aug 2021 15:08:04 +0000 https://www.wikitechy.com/interview-questions/?p=1797

A train of length 110 meters is running at a speed of 60 kmph. In what time, it will pass a man who is running at 6 kmph in the direction opposite to that in which the train is going ?

A. 10

B. 8

C. 6

D. 4

Answer : C. 6

Explanation :

Distance = 110 m
Relative speed = 60 + 6 = 66 kmph ( Since both the train and the man are in moving in opposite direction )
= (66 * 5 / 18) m/sec
= 55 / 3 m/sec

Time taken to pass the man = (100 * 3/ 55) = 6 s

]]> https://www.wikitechy.com/interview-questions/problems-on-trains/a-train-of-length-110-meters-is-running-at-a-speed-of-60-kmph-in-what-time-it-will-pass-a-man-who-is-running-at-6-kmph-in-the-direction-opposite-to-that-in-which-the-train-is-going/feed/ 0 Vijay invested Rs.50,000 partly at 10% and partly at 15%. His total income after a year was Rs.7000. How much did he invest at the rate of 10% ? https://www.wikitechy.com/interview-questions/compound-interest/vijay-invested-rs-50000-partly-at-10-and-partly-at-15-his-total-income-after-a-year-was-rs-7000-how-much-did-he-invest-at-the-rate-of-10/ https://www.wikitechy.com/interview-questions/compound-interest/vijay-invested-rs-50000-partly-at-10-and-partly-at-15-his-total-income-after-a-year-was-rs-7000-how-much-did-he-invest-at-the-rate-of-10/#respond Tue, 17 Aug 2021 14:59:21 +0000 https://www.wikitechy.com/interview-questions/?p=1788

Vijay invested Rs.50,000 partly at 10% and partly at 15%. His total income after a year was Rs.7000. How much did he invest at the rate of 10% ?

A. 40,000

B. 41,000

C. 12,000

D. 20,000

Answer : A. 40,000…

Explanation :

Let the amount Vijay invested at the rate of 10% = Rs x
The amount invested at 15% = Rs (50,000 – x)
Time = 1yr
Income from 10% rate = 10% of x = x/10
Income from 15% rate = 15% of (50,000 – x) = (150,000 – 3x)/20

According to question,
[x/10] + [(150,000 – 3x)/20] = 7000
150000 – x = 140000
x = 10,000.
Therefore, he has invested Rs 10,000 at 10% and Rs 40,000 at 15%.

]]> https://www.wikitechy.com/interview-questions/compound-interest/vijay-invested-rs-50000-partly-at-10-and-partly-at-15-his-total-income-after-a-year-was-rs-7000-how-much-did-he-invest-at-the-rate-of-10/feed/ 0 Rs.5887 is divided between Shyam and Ram, such that Shyam’s share at the end of 9 years is equal to Ram’s share at the end of 11 years, compounded annually at the rate of 5%. Find the share of Shyam ? https://www.wikitechy.com/interview-questions/compound-interest/rs-5887-is-divided-between-shyam-and-ram-such-that-shyams-share-at-the-end-of-9-years-is-equal-to-rams-share-at-the-end-of-11-years-compounded-annually-at-the-rate-of-5-find-the-s/ https://www.wikitechy.com/interview-questions/compound-interest/rs-5887-is-divided-between-shyam-and-ram-such-that-shyams-share-at-the-end-of-9-years-is-equal-to-rams-share-at-the-end-of-11-years-compounded-annually-at-the-rate-of-5-find-the-s/#respond Tue, 17 Aug 2021 14:57:11 +0000 https://www.wikitechy.com/interview-questions/?p=1787

Rs.5887 is divided between Shyam and Ram, such that Shyam’s share at the end of 9 years is equal to Ram’s share at the end of 11 years, compounded annually at the rate of 5%. Find the share of Shyam ?

A. 2088

B. 2000

C. 3087

D. None of these

Answer : C. 3087…

Explanation :

Shyam’s share * (1 + 0.05)9 = Ram’s share * (1 + 0.05)11
Shyam’s share / Ram’s share = (1 + 0.05)11 / (1 + 0.05)9
= (1 + 0.05)2
= 441/400
Therefore Shyam’s share = (441/841) * 5887
= 3087 .

]]> https://www.wikitechy.com/interview-questions/compound-interest/rs-5887-is-divided-between-shyam-and-ram-such-that-shyams-share-at-the-end-of-9-years-is-equal-to-rams-share-at-the-end-of-11-years-compounded-annually-at-the-rate-of-5-find-the-s/feed/ 0 A certain sum amounts to Rs. 7000 in 2 years and to Rs. 8000 in 3 years. Find the sum ? https://www.wikitechy.com/interview-questions/compound-interest/a-certain-sum-amounts-to-rs-7000-in-2-years-and-to-rs-8000-in-3-years-find-the-sum/ https://www.wikitechy.com/interview-questions/compound-interest/a-certain-sum-amounts-to-rs-7000-in-2-years-and-to-rs-8000-in-3-years-find-the-sum/#respond Tue, 17 Aug 2021 14:54:50 +0000 https://www.wikitechy.com/interview-questions/?p=1786

A certain sum amounts to Rs. 7000 in 2 years and to Rs. 8000 in 3 years. Find the sum ?

A. Rs 6959.37

B. Rs 6459.37

C. Rs 5359.37

D. Rs 5759.37

Answer : C. Rs 5359.37…

Explanation :

Amount = Rs. 7000, Time = 2 years
Amount = Rs. 8000, Time = 3 years
To calculate sum, we must first calculate rate of interest.
Simple interest = PRN / 100

S.I. on Rs. 7000 for 1 year = Rs. (8000 – 7000) = Rs. 1000
1000 = 7000 × R × 1 / 100
R = 11 23/7%
Let sum be Rs. X
7000 = P [ 1 + ( 100 / 7 × 100 ) ]2
8 / 7 × 8 / 7 × P = 7000
P = 5359.37

]]> https://www.wikitechy.com/interview-questions/compound-interest/a-certain-sum-amounts-to-rs-7000-in-2-years-and-to-rs-8000-in-3-years-find-the-sum/feed/ 0 Find the compound interest on Rs. 20,000 in 2 years at 4 % per annum, the interest being compounded half-yearly ? https://www.wikitechy.com/interview-questions/compound-interest/find-the-compound-interest-on-rs-20000-in-2-years-at-4-per-annum-the-interest-being-compounded-half-yearly/ https://www.wikitechy.com/interview-questions/compound-interest/find-the-compound-interest-on-rs-20000-in-2-years-at-4-per-annum-the-interest-being-compounded-half-yearly/#respond Tue, 17 Aug 2021 14:52:16 +0000 https://www.wikitechy.com/interview-questions/?p=1785

Find the compound interest on Rs.20,000 in 2years at 4% per annum, the interest being compounded half-yearly ?

A. Rs 1648.64

B. Rs 1596.32

C. Rs 14826.56

D. Rs 11563.99

Answer : A. Rs 1648.64…

Explanation :

Interest is compounded half-yearly, therefore,
Amount = P ( 1 + (R/2) /100 )2n – – – – – – – – – [Interest compounded Half-yearly]

Given :
Principal = Rs. 20000,
Rate = 2 % per half-year,
Time = 2 years = 4 half- years
Amount = 20000 [ 1 + 2 / 100 ]4
Amount = Rs.21648.64
Compound Interest = Total amount – Principal
= 21648.64 – 20000
= Rs. 1648.64

]]> https://www.wikitechy.com/interview-questions/compound-interest/find-the-compound-interest-on-rs-20000-in-2-years-at-4-per-annum-the-interest-being-compounded-half-yearly/feed/ 0 A property decreases in value every year at the rate of 6 1/4% of its value at the beginning of the year its value at the end of 3 years was Rs.21093. Find its value at the beginning of the first year ? https://www.wikitechy.com/interview-questions/compound-interest/a-property-decreases-in-value-every-year-at-the-rate-of-6-1-4-of-its-value-at-the-beginning-of-the-year-its-value-at-the-end-of-3-years-was-rs-21093-find-its-value-at-the-beginning-of-the-first-year/ https://www.wikitechy.com/interview-questions/compound-interest/a-property-decreases-in-value-every-year-at-the-rate-of-6-1-4-of-its-value-at-the-beginning-of-the-year-its-value-at-the-end-of-3-years-was-rs-21093-find-its-value-at-the-beginning-of-the-first-year/#respond Tue, 17 Aug 2021 14:39:05 +0000 https://www.wikitechy.com/interview-questions/?p=1783

A property decreases in value every year at the rate of 6 1/4% of its value at the beginning of the year its value at the end of 3 years was Rs.21093. Find its value at the beginning of the first year ?

A. Rs 25600.24

B. Rs 32000.50

C. Rs 18060.26

D. Rs 18600

Answer : A. Rs 25600.24…

Explanation :

6 1/4% = 1/16
x * (15/16) * (15/16) * (15/16) = 21093
x = 25600.24

]]> https://www.wikitechy.com/interview-questions/compound-interest/a-property-decreases-in-value-every-year-at-the-rate-of-6-1-4-of-its-value-at-the-beginning-of-the-year-its-value-at-the-end-of-3-years-was-rs-21093-find-its-value-at-the-beginning-of-the-first-year/feed/ 0 A sum of money place at compound interest doubles itself in 4 years. In how many years will it amount to eight times itself ? https://www.wikitechy.com/interview-questions/compound-interest/a-sum-of-money-place-at-compound-interest-doubles-itself-in-4-years-in-how-many-years-will-it-amount-to-eight-times-itself/ https://www.wikitechy.com/interview-questions/compound-interest/a-sum-of-money-place-at-compound-interest-doubles-itself-in-4-years-in-how-many-years-will-it-amount-to-eight-times-itself/#respond Tue, 17 Aug 2021 14:36:54 +0000 https://www.wikitechy.com/interview-questions/?p=1782

A sum of money place at compound interest doubles itself in 4 years. In how many years will it amount to eight times itself ?

A. 16

B. 8

C. 12

D. 20

Answer : C. 12…

Explanation :

Let, Principal = Rs. 100.
Amount = Rs. 200.
Rate = r%
Time = 4 years.

Now,
A = P * [ 1 + (r/100) ]n
200 = 100 * [ 1 + (r/100) ]4
2 = [1 + (r/100)]4 ……….. (i)
If sum become 8 times in the time n years, then,
8 = ( 1 + (r/100) )n
23 = ( 1 + (r/100) )n …….. (ii)

Using eqn (i) in (ii), we get
( [1 + (r/100) ]4)3 = ( 1 + (r/100) )n
[1 + (r/100)]12 = (1 + (r/100))n
n = 12 years.

]]> https://www.wikitechy.com/interview-questions/compound-interest/a-sum-of-money-place-at-compound-interest-doubles-itself-in-4-years-in-how-many-years-will-it-amount-to-eight-times-itself/feed/ 0 Rs.8000 become Rs.9261 in a certain interval of time at the rate of 5% per annum of C.I. Find the time ? https://www.wikitechy.com/interview-questions/compound-interest/rs-8000-become-rs-9261-in-a-certain-interval-of-time-at-the-rate-of-5-per-annum-of-c-i-find-the-time/ https://www.wikitechy.com/interview-questions/compound-interest/rs-8000-become-rs-9261-in-a-certain-interval-of-time-at-the-rate-of-5-per-annum-of-c-i-find-the-time/#respond Tue, 17 Aug 2021 14:34:24 +0000 https://www.wikitechy.com/interview-questions/?p=1781

Rs.8000 become Rs.9261 in a certain interval of time at the rate of 5% per annum of C.I. Find the time ?

A. 4 years

B. 6 years

C. 2 years

D. 3 years

Answer : D. 3 years…

Explanation :

Amount = 9261 p = 8000
rate = 5%
A = p [ 1 + r / 100]n
9261 = 8000[1 + 5/100]n
=> 9261 / 8000 = [21 / 20]n
=> [21 / 20]3=[21 / 20]n
on comparing n = 3 so it will take 3years

]]> https://www.wikitechy.com/interview-questions/compound-interest/rs-8000-become-rs-9261-in-a-certain-interval-of-time-at-the-rate-of-5-per-annum-of-c-i-find-the-time/feed/ 0