\n
A square field of area 31684 m2<\/sup>\u00a0is to be enclosed with the wireplaced at height 1 m, 2 m, 3 m, 4 m above the ground. What length of the wire will be required if its length required for each circuit is 5% greater than the perimeter of the field ?<\/p>\n\n
\n
A. 6456 m<\/p>\n<\/div>\n
\n
B. 27666 m<\/p>\n<\/div>\n
\n
C. 2990.4 m<\/p>\n<\/div>\n
\n
D. 14<\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n
Answer :\u00a0<\/b>C. 2990.4 m<\/h3>\n\n
Explanation:<\/h2>\n<\/div>\n\n
\n
Given that a square field is to be enclosed by four wires at height 1m, 2m, 3m and 4m.<\/strong><\/p>\nArea of the square field = 31684 m2<\/sup><\/b>
\nLet’s find the perimeter of square<\/p>\nAs we know<\/strong><\/p>\nArea of square = x2<\/sup><\/b>
\nSo,
\nx2<\/sup>\u00a0= 31684 m2<\/sup>
\nTaking square root on both sides
\n\u221ax2<\/sup>\u00a0= \u221a31684 m2<\/sup>
\nx = 178 m
\nSo, the length of one side of square is x = 178 m<\/p>\nAs we know the perimeter of the square is calculated as<\/strong><\/p>\nP = 4x
\nP = 4 * 178
\nP = 712 m<\/p>\n
Given that length of wire for each circuit is 5% more than the length of perimeter of square. So,<\/strong><\/p>\nLength of wire = Length of perimeter \u00a0+ 5% of Length of perimeter \u00a0<\/b>
\nl = 712 + 0.05 * 712
\nl = 712 + 35.6
\nl = 747.6 m<\/p>\n
As we need to enclose the square field by wires four times at different height; therefore,<\/strong><\/p>\nTotal Length of wire = 4l
\nTotal Length of wire = 4 * 747.6
\nTotal Length of wire = 2990.4 m<\/p>\n
So, total length of wire is\u00a02990.4 m<\/b><\/p>\n<\/div>\n<\/div>\n<\/div>\n","protected":false},"excerpt":{"rendered":"
Answer :\u00a0C. 2990.4 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