# Java Programming – Length of the largest subarray with contiguous elements

An array of distinct integers, find length of the longest subarray which contains numbers that can be arranged in a continuous sequence.

Given an array of distinct integers, find length of the longest subarray which contains numbers that can be arranged in a continuous sequence.

Examples:

```Input:  arr[] = {10, 12, 11};
Output: Length of the longest contiguous subarray is 3

Input:  arr[] = {14, 12, 11, 20};
Output: Length of the longest contiguous subarray is 2

Input:  arr[] = {1, 56, 58, 57, 90, 92, 94, 93, 91, 45};
Output: Length of the longest contiguous subarray is 5```

The important thing to note in question is, it is given that all elements are distinct. If all elements are distinct, then a subarray has contiguous elements if and only if the difference between maximum and minimum elements in subarray is equal to the difference between last and first indexes of subarray. So the idea is to keep track of minimum and maximum element in every subarray.

The following is the implementation of above idea.

Java Program
``````class LargestSubArray2
{
// Utility functions to find minimum and maximum of
// two elements

int min(int x, int y)
{
return (x < y) ? x : y;
}

int max(int x, int y)
{
return (x > y) ? x : y;
}

// Returns length of the longest contiguous subarray
int findLength(int arr[], int n)
{
int max_len = 1;  // Initialize result
for (int i = 0; i < n - 1; i++)
{
// Initialize min and max for all subarrays starting with i
int mn = arr[i], mx = arr[i];

// Consider all subarrays starting with i and ending with j
for (int j = i + 1; j < n; j++)
{
// Update min and max in this subarray if needed
mn = min(mn, arr[j]);
mx = max(mx, arr[j]);

// If current subarray has all contiguous elements
if ((mx - mn) == j - i)
max_len = max(max_len, mx - mn + 1);
}
}
return max_len;  // Return result
}

public static void main(String[] args)
{
LargestSubArray2 large = new LargestSubArray2();
int arr[] = {1, 56, 58, 57, 90, 92, 94, 93, 91, 45};
int n = arr.length;
System.out.println("Length of the longest contiguous subarray is "
+ large.findLength(arr, n));
}
}``````

Output:

`Length of the longest contiguous subarray is 5`

Time Complexity of the above solution is O(n2).

READ  Java Programming - Largest Sum Contiguous Subarray #### Wikitechy Editor

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