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		<title>What is N Queen Problem ?</title>
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		<pubDate>Tue, 13 Jul 2021 11:31:06 +0000</pubDate>
				<category><![CDATA[Data Structure]]></category>
		<category><![CDATA[4 queen problem]]></category>
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					<description><![CDATA[Answer : Let us discuss N Queen problem that can be solved using Backtracking...]]></description>
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<h2 id="n-queen-problem" class="color-pink" style="text-align: justify;">N Queen Problem</h2>
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<li>Let us discuss N Queen problem that can be solved using <a href="https://www.wikitechy.com/final-year-project/dotnet/server-hacking/backtracking-algorithm" target="_blank" rel="noopener">Backtracking</a>.</li>
<li>The N Queen is the problem of placing N chess queens on an N×N chessboard so that no two queens attack each other. For example, following the solution for 4 Queen problem.</li>
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<div class="hddn"><img decoding="async" class="img-responsive center-block aligncenter" src="https://cdn.wikitechy.com/interview-questions/data-structure/what-is-n-queen-problem.jpg" alt=" N Queen Problem" /></div>
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<li>Binary <a href="https://www.wikitechy.com/tutorials/apache-pig/apache-pig-tutorial/matrix-multiplication-apache-pig" target="_blank" rel="noopener">matrix</a> which has 1&#8217;s for the blocks where queens are placed. For example, following is the output matrix for above 4 queen solution.</li>
</ul>
<div class="code-embed-wrapper"> <div class="code-embed-infos"> </div> <pre class="language-markdown code-embed-pre line-numbers"  data-start="1" data-line-offset="0"><code class="language-markdown code-embed-code">{ 0,  1,  0,  0 }<br/>{ 0,  0,  0,  1 }<br/>{ 1,  0,  0,  0 }<br/>{ 0,  0,  1,  0 }</code></pre> </div>
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<h2 id="backtracking-algorithm" class="color-green">Backtracking Algorithm</h2>
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<li>The idea is to place queens one by one in different columns, starting from the leftmost column.</li>
<li>When we place a queen in a column, we can checkout to clashes with already placed queens.</li>
<li>In the current column, if we find a row for which there is no clash, we mark this row and column as part of the solution.</li>
<li>If we do not find such a row due to clashes then we backtrack and return false.</li>
</ul>
<div class="code-embed-wrapper"> <div class="code-embed-infos"> </div> <pre class="language-markdown code-embed-pre line-numbers"  data-start="1" data-line-offset="0"><code class="language-markdown code-embed-code">1) Start from the leftmost column<br/>2) If all queens are placed<br/>    return true<br/>3) Try all rows in the current column.  Do following for every tried row.<br/>    a) If the queen can be placed safely in this row then mark this [row, <br/>        column] as part of the solution and recursively check if placing queen here leads to a solution.<br/>    b) If placing the queen in [row, column] leads to a solution then return <br/>        true.<br/>    c) If placing queen does not lead to a solution then umark this [row, <br/>        column] (Backtrack) and go to step (a) to try other rows.<br/>4) If all rows have been tried and nothing worked, return false to trigger <br/>    backtracking.</code></pre> </div>
<h2 id="sample-code-in-c" class="color-blue">Sample Code in C</h2>
<div class="code-embed-wrapper"> <div class="code-embed-infos"> </div> <pre class="language-c code-embed-pre line-numbers"  data-start="1" data-line-offset="0"><code class="language-c code-embed-code">/* C/C++ program to solve N Queen Problem using <br/>backtracking */<br/>#define N 4 <br/>#include&lt;stdio.h&gt; <br/>#include&lt;stdbool.h&gt; <br/><br/>/* A utility function to print solution */<br/>void printSolution(int board[N][N]) <br/>{ <br/>	for (int i = 0; i &lt; N; i++) <br/>	{ <br/>		for (int j = 0; j &lt; N; j++) <br/>			printf(&quot; %d &quot;, board[i][j]); <br/>		printf(&quot;\n&quot;); <br/>	} <br/>} <br/><br/>/* A utility function to check if a queen can be placed on board[row][col]. <br/>Note that this function is called when &quot;col&quot; queens are already placed in columns<br/> from 0 to col -1. So we need to check only left side for attacking queens */<br/>bool isSafe(int board[N][N], int row, int col) <br/>{ <br/>	int i, j; <br/><br/>	/* Check this row on left side */<br/>	for (i = 0; i &lt; col; i++) <br/>		if (board[row][i]) <br/>			return false; <br/><br/>	/* Check upper diagonal on left side */<br/>	for (i=row, j=col; i&gt;=0 &amp;&amp; j&gt;=0; i--, j--) <br/>		if (board[i][j]) <br/>			return false; <br/><br/>	/* Check lower diagonal on left side */<br/>	for (i=row, j=col; j&gt;=0 &amp;&amp; i&lt;N; i++, j--) <br/>		if (board[i][j]) <br/>			return false; <br/><br/>	return true; <br/>} <br/><br/>/* A recursive utility function to solve N <br/>Queen problem */<br/>bool solveNQUtil(int board[N][N], int col) <br/>{ <br/>	/* base case: If all queens are placed <br/>	then return true */<br/>	if (col &gt;= N) <br/>		return true; <br/><br/>	/* Consider this column and try placing <br/>	this queen in all rows one by one */<br/>	for (int i = 0; i &lt; N; i++) <br/>	{ <br/>		/* Check if the queen can be placed on <br/>		board[i][col] */<br/>		if ( isSafe(board, i, col) ) <br/>		{ <br/>			/* Place this queen in board[i][col] */<br/>			board[i][col] = 1; <br/><br/>			/* recur to place rest of the queens */<br/>			if ( solveNQUtil(board, col + 1) ) <br/>				return true; <br/><br/>			/* If placing queen in board[i][col] <br/>			doesn&#039;t lead to a solution, then <br/>			remove queen from board[i][col] */<br/>			board[i][col] = 0; // BACKTRACK <br/>		} <br/>	} <br/><br/>	/* If the queen cannot be placed in any row in <br/>		this colum col then return false */<br/>	return false; <br/>} <br/><br/>/* This function solves the N Queen problem using Backtracking. It mainly uses <br/>solveNQUtil() to solve the problem. It returns false if queens cannot be placed, <br/>otherwise, return true and prints placement of queens in the form of 1s.<br/><br/> Please note that there may be more than one solutions, this function prints one of the <br/>feasible solutions.*/<br/>bool solveNQ() <br/>{ <br/>	int board[N][N] = { {0, 0, 0, 0}, <br/>		{0, 0, 0, 0}, <br/>		{0, 0, 0, 0}, <br/>		{0, 0, 0, 0} <br/>	}; <br/><br/>	if ( solveNQUtil(board, 0) == false ) <br/>	{ <br/>	printf(&quot;Solution does not exist&quot;); <br/>	return false; <br/>	} <br/><br/>	printSolution(board); <br/>	return true; <br/>} <br/><br/>// driver program to test above function <br/>int main() <br/>{ <br/>	solveNQ(); <br/>	return 0; <br/>}</code></pre> </div>
<h2 id="output" class="color-blue">Output</h2>
<div class="code-embed-wrapper"> <div class="code-embed-infos"> </div> <pre class="language-c code-embed-pre line-numbers"  data-start="1" data-line-offset="0"><code class="language-c code-embed-code">0  0  1  0 <br/> 1  0  0  0 <br/> 0  0  0  1 <br/> 0  1  0  0 </code></pre> </div>
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