[Solved-6 Solutions] HTML text input allows only numeric input - javascript Tutorial
Problem:
Is there a quick way to set an HTML text input (<input type=text />) to allow numeric keystrokes (plus '.')?
Solution 1:
Here we can use JS Validation. It will work for numeric keypad and normal number key's
function isNumberKey(evt){
var charCode = (evt.which) ? evt.which : event.keyCode
if (charCode < 31 || (charCode >= 48 && charCode <= 57 ) || (charCode >= 96 && charCode <= 105 ))
return true;
return false;
}
<input name="someid" type="number" onkeypress="return isNumberKey(event)"/%>Solution 2:
Using keys and other non-typeable keys to combined for a complete JavaScript. It is also supports input of type number and max length validation.
jQuery
$(document).ready(function() {
$("#txtboxToFilter").keydown(function (e) {
// Allow: backspace, delete, tab, escape, enter and .
if ($.inArray(e.keyCode, [46, 8, 9, 27, 13, 110, 190]) !== -1 ||
// Allow: Ctrl/cmd+A
(e.keyCode == 65 && (e.ctrlKey === true || e.metaKey === true)) ||
// Allow: Ctrl/cmd+C
(e.keyCode == 67 && (e.ctrlKey === true || e.metaKey === true)) ||
// Allow: Ctrl/cmd+X
(e.keyCode == 88 && (e.ctrlKey === true || e.metaKey === true)) ||
// Allow: home, end, left, right
(e.keyCode >= 35 && e.keyCode <= 39)) {
// let it happen, don't do anything
return;
}
// Ensure that it is a number and stop the keypress
if ((e.shiftKey || (e.keyCode < 48 || e.keyCode > 57)) && (e.keyCode < 96 || e.keyCode > 105)) {
e.preventDefault();
}
});
});
jQuery
// Allow: backspace, delete, tab, escape, enter and .
if ($.inArray(e.keyCode, [46, 8, 9, 27, 13, 110, 190]) !== -1 ||
// Allow: Ctrl+A
(e.keyCode == 65 && (e.ctrlKey === true || e.metaKey === true)) ||
// Allow: Ctrl+C
(e.keyCode == 67 && (e.ctrlKey === true || e.metaKey === true)) ||
// Allow: Ctrl+X
(e.keyCode == 88 && (e.ctrlKey === true || e.metaKey === true)) ||
// Allow: home, end, left, right
(e.keyCode >= 35 && e.keyCode <= 39) ||
//Allow numbers and numbers + shift key
((e.shiftKey && (e.keyCode >= 48 && e.keyCode <= 57)) || (e.keyCode >= 96 && e.keyCode <= 105))) {
// let it happen, don't do anything
return;
}
// Ensure that it is a number and stop the keypress
if ((!e.shiftKey && (e.keyCode < 48 || e.keyCode > 57)) || (e.keyCode < 96 || e.keyCode > 105)) {
e.preventDefault();
}
Solution 3:
Use this DOM
<input type='text' onkeypress='validate(event)' />
And this script
function validate(evt) {
var theEvent = evt || window.event;
var key = theEvent.keyCode || theEvent.which;
key = String.fromCharCode( key );
var regex = /[0-9]|\./;
if( !regex.test(key) ) {
theEvent.returnValue = false;
if(theEvent.preventDefault) theEvent.preventDefault();
}
}
Solution 4:
We need <input type="number">.
<input type="text"
onkeyup="this.value=this.value.replace(/[^\d]/,'')">
The non-accepted character showing to erased by using this code.
<input type="text"
onkeydown="return ( event.ctrlKey || event.altKey
|| (47<event.keyCode && event.keyCode<58 && event.shiftKey==false)
|| (95<event.keyCode && event.keyCode<106)
|| (event.keyCode==8) || (event.keyCode==9)
|| (event.keyCode>34 && event.keyCode<40)
|| (event.keyCode==46) )">
Solution 5:
HTML5 has <input type=number>, which sounds right for you. Currently, only Opera supports it natively, but there is a project that has a JavaScript implementation.
Solution 6:
Using this code:
function validateNumber(event) {
var key = window.event ? event.keyCode : event.which;
if (event.keyCode === 8 || event.keyCode === 46) {
return true;
} else if ( key < 48 || key > 57 ) {
return false;
} else {
return true;
}
};Keypress event also to be attach:
$(document).ready(function(){
$('[id^=edit]').keypress(validateNumber);
});
Using HTML :
<input type="input" id="edit1" value="0" size="5" maxlength="5" />