#include<stdio.h>
#include<conio.h>
void main()
{
clrscr();
long int i=0;
char binarynum[100], hexdec[100];
printf("Enter Hexadecimal Value : ");
scanf("%s",hexdec);
printf("\nEqual Binary value is : ");
while(hexdec[i])
{
switch(hexdec[i])
{
case '0' : printf("0000");
break;
case '1' : printf("0001");
break;
case '2' : printf("0010");
break;
case '3' : printf("0011");
break;
case '4' : printf("0100");
break;
case '5' : printf("0101");
break;
case '6' : printf("0110");
break;
case '7' : printf("0111");
break;
case '8' : printf("1000");
break;
case '9' : printf("1001");
break;
case 'A' : printf("1010");
break;
case 'B' : printf("1011");
break;
case 'C' : printf("1100");
break;
case 'D' : printf("1101");
break;
case 'E' : printf("1110");
break;
case 'F' : printf("1111");
break;
case 'a' : printf("1010");
break;
case 'b' : printf("1011");
break;
case 'c' : printf("1100");
break;
case 'd' : printf("1101");
break;
case 'e' : printf("1110");
break;
case 'f' : printf("1111");
break;
default : printf("\nInvalid hexadecimal digit %c",hexdec[i]);
}
i++;
}
getch();
}
Output
Enter Hexadecimal Value : AB1c
Equal Binary value is : 1010101100011100
Hexadecimal and Binary Values
Hex |
Decimal |
Binary |
0 |
0 |
0000 |
1 |
1 |
0001 |
2 |
2 |
0010 |
3 |
3 |
0011 |
4 |
4 |
0100 |
5 |
5 |
0101 |
6 |
6 |
0110 |
7 |
7 |
0111 |
8 |
8 |
1000 |
9 |
9 |
1001 |
A |
10 |
1010 |
B |
11 |
1011 |
C |
12 |
1100 |
D |
13 |
1101 |
E |
14 |
1110 |
F |
15 |
1111 |
- We want to convert hexadecimal number AB1c to binary. For this we will replace each hexadecimal digit to binary values using the above table:
Hexadecimal Number: A B 1 c
Binary Values: (1010) (1011) (0001) (1100)
So (AB1c)16 = (1010101100011100)2