Find the area of Rhombus one of whose diagonals measures 8 cm and the other 10 cm ?

Area of triangle formula = 1/2*(base)*(height)
Area of one triangle = 1/2 * (4) * (5)
= 10 cm².

Total area of rhombus = 4 * area of one triangle
= 4 * 10
= 40 cm²

Area of a rhombus is = 1/2 * (length of one diagonal) * (length of another diagonal)
= 1/2 * 8 * 10 cm²
= 40 cm²