For any two numbers we define an operation $ yielding another number, X $ Y such that following condition holds: ” X $ X = 0 for all X ” X $ (Y $ Z) = X $ Y + Z Find the Value of 2012 $ 0 + 2012 $ 1912 ?
A. 2112
B. 100
C. 5936
D. Cannot be determined
Answer : A. 2112
Explanation:
Here $ represent the – operator so X – X = 0
First condition x $ (y $ z) = x – (y – z) = x – y + z.
It can be written as x $ y + z
2012 – 0 + 2012 – 1912 = 2112
