Three unbiased coins are tossed. What is the probability of getting at most two heads ?
Three unbiased coins are tossed. What is the probability of getting at most two heads ?
A. 3/4
B. 1/4
C. 3/8
D. 7/8
Answer : D. 7/8…
Explanation:
Here, S = {TTT, TTH, THT, HTT, THH, HTH, HHT, HHH}
Let E = event of getting at most two heads.
Then E = {TTT, TTH, THT, HTT, THH, HTH, HHT}
P(E) = n(E)/n(S)
= 7/8.
