Two cards are drawn together from a pack of 52 cards. The probability that one is a club and one is a diamond ?

A. 13/51

B. 1/52

C. 13/102

D. 1/26

Answer : C. 13/102…

Explanation:

n(S) = Total number of ways of drawing 2 cards from 52 cards = 52C2.
Let E = event of getting 1 club and 1 diamond.
We know that there are 13 clubs and 13 diamonds in the total 52 cards.
Hence, n(E) = Number of ways of drawing one club from 13 and one diamond from 13 = 13C1 × 13C1 = 13/102
P(E) = n(E)/n(S)
= (13C1 × 13C1) / 52C2
= 13/102.

Categorized in:

Probability

Tagged in:

, , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , ,

Share Article:

Leave a Reply

Ads Blocker Image Powered by Code Help Pro

Ads Blocker Detected!!!

We have detected that you are using extensions to block ads. Please support us by disabling these ads blocker.

Powered By
100% Free SEO Tools - Tool Kits PRO