What is the smallest number that leaves a remainder of 2 when divided by 3, 4, 5, and 6 ?
What is the smallest number that leaves a remainder of 2 when divided by 3, 4, 5, and 6 ?
A. 56
B. 128
C. 62
D. 32
Answer : C. 62
Explanation:
Take the lcm of 3 , 4 , 5 , 6.
3 = 3×1
4 = 2×2
5 = 5×1
6 = 2×3
LCM = 2 × 2 × 3 × 5 = 60
Therefore 60 is the number that is completely divisible by these numbers. But we have to find the smallest number that leaves remainder 2.
Answer : 60 + 2 = 62
