Find the value of log (a2 / bc) + log (b2 / ac) + log (c2 / ab) ?
A. 0
B. 1
C. abc
D. ab2c2
Answer : A. 0…
Explanation:
logX + logY = log (XY)
= log (a2/bc) + log (b2/ac) + log (c2/ab)
= log (a2 b2 c2 / bcacab)
= log (a2 b2c2 / a2b2c2)
= log 1
= 0
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